# Trapezoid - RR

Find the area of the right angled trapezoid ABCD with the right angle at the A vertex;

a = 3 dm b = 5 dm c = 6 dm d = 4 dm

Correct result:

S =  18 dm2

#### Solution:

$a=3 \ \text{dm} \ \\ b=5 \ \text{dm} \ \\ c=6 \ \text{dm} \ \\ d=4 \ \text{dm} \ \\ S=(a+c)/2 \cdot \ d=(3+6)/2 \cdot \ 4=18 \ \text{dm}^2$

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