Polynomial roots

Find the other zeroes of the polynomial 2x4+3x3-3x2-6x-2, if two of them are root2 & -root2

Correct answer:

x3 =  -0.5
x4 =  -1

Step-by-step explanation:

x1=2=21.4142 x2=2=21.4142  (xx1)(xx2)=x22 2x4+3x33x26x2=(x22)(2x2+3x+1)  2z2+3z+1=0  2z2+3z+1=0 2z2+3z+1=0  a=2;b=3;c=1 D=b24ac=32421=1 D>0  z1,2=b±D2a=3±14 z1,2=3±14 z1,2=0.75±0.25 z1=0.5 z2=1   Factored form of the equation:  2(z+0.5)(z+1)=0  x3=z1=(0.5)=0.5

Our quadratic equation calculator calculates it.

x4=z2=(1)=1



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