Diagonal 20

The rectangular town plaza's diagonal pathway is 20 m longer than the width. Suppose the pathway is 20 m shorter than twice the width. How long should the pathway be?

Correct answer:

x =  100 m

Step-by-step explanation:

a = 20 + b x = a2+b2 x = 2 b 20 (2 b20)2=(20+b)2+b2  (2 b20)2=(20+b)2+b2 2b2120b=0 2 ...  prime number 120=2335 0 GCD(2,120,0)=2  b260b=0  p=1;q=60;r=0 D=q24pr=602410=3600 D>0  b1,2=2pq±D=260±3600 b1,2=260±60 b1,2=30±30 b1=60 b2=0 b>0 b=b1=60 m a=20+b=20+60=80 m x=a2+b2=802+602=100 m

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