Water

Mix 68 l of water with a temperature of 87 °C, 17 l warm of 42 °C, and 55 l water of 50 °C.

What is the temperature of the mixed water immediately after mixing?

Correct result:

t =  67 °C

Solution:

$$\begin{gathered} V_1=68\text{ l } \\ {V}_2=17\text{ l } \\ {V}_3=55\text{ l } \\ {t}_1=87^{\circ }\text{C } \\ {t}_2=42^{\circ }\text{C } \\ {t}_3=50^{\circ }\text{C } \\ t={\displaystyle \frac{V_1\cdot t_1+V_2\cdot t_2+V_3\cdot t_3}{V_1+V_2+V_3}}={\displaystyle \frac{68\cdot 87+17\cdot 42+55\cdot 50}{68+17+55}}=67^{\circ }\text{C} \end{gathered}$$

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