Regular quadrangular pyramid

The height of the regular quadrangular pyramid is 6 cm, the length of the base is 4 cm. What is the angle between the ABV and BCV planes?

Correct result:

x =  36.8699 °

Solution:

h=6 cm a=4 cm  s1=a/2=4/2=2 cm s2=s12+h2=22+62=2 10 cm≐6.3246 cm  tan⁡x/2=s1/h  x=2⋅ 180∘π⋅arctan⁡(s1/h)=2⋅ 180∘π⋅arctan⁡(2/6)=36.8699∘=36∘52′12"

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