Angle of two lines

There is a regular quadrangular pyramid ABCDV; | AB | = 4 cm; height v = 6 cm. Determine the angles of lines AD and BV.

Correct answer:

α =  72.4516 °

Step-by-step explanation:

a=4 cm v=6 cm  s=v2+(a/2)2=62+(4/2)2=2 10 cm6.3246 cm  tanα=s/(a/2)  α1=arctan(2 s/a)=arctan(2 6.3246/4)1.2645 rad  α=α1  °=α1 π180   °=1.2645 π180   °=72.452  °=72.4516=72°276"



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