Angle of two lines

There is a regular quadrangular pyramid ABCDV; | AB | = 4 cm; height v = 6 cm. Determine the angles of lines AD and BV.

Correct result:

X =  72.4516 °

Solution:

a=4 cm v=6 cm  s=v2+(a/2)2=62+(4/2)2=2 10 cm≐6.3246 cm  tan⁡X=s/(a/2)  X1=arctan⁡(2⋅ s/a)=arctan⁡(2⋅ 6.3246/4)≐1.2645 rad  X=X1→∘=X1⋅ 180π∘=1.2645⋅ 180π∘=72.452∘=72.4516∘=72∘27′6"

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