Angle of two lines

There is a regular quadrangular pyramid ABCDV; | AB | = 4 cm; height v = 6 cm. Determine the angles of lines AD and BV.

Correct result:

X =  72.4516 °

Solution:

a=4 cm v=6 cm  s=v2+(a/2)2=62+(4/2)2=2 10 cm6.3246 cm  tanX=s/(a/2)  X1=arctan(2 s/a)=arctan(2 6.3246/4)1.2645 rad  X=X1=X1 180π=1.2645 180π=72.452=72.4516=72276"



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