Height of pyramid

The pyramid ABCDV has edge lengths: AB = 4, AV = 7. What is its height?

Correct result:

h =  6.4031

Solution:

a=4 s=7  u=2⋅ a=2⋅ 4=4 2≐5.6569  h2=s2−(u/2)2  h=s2−(u/2)2=72−(5.6569/2)2=41=6.4031

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