Cylinder 6379

The cylinder has a base diameter of 0.8 m. The area of the base is equal to the area of the casing. How much water can be poured into the cylinder?

Correct answer:

V =  100.531 l

Step-by-step explanation:

$$\begin{gathered} D=0.8\text{m} \\ r=D/2=0.8/2=\frac{2}{5}=0.4\text{m} \\ S=\pi \cdot r^2=3.1416\cdot 0.4^2\doteq 0.5027{\text{m}}^2 \\ S=\pi \cdot D\cdot h \\ h=S/(\pi \cdot D)=0.5027/(3.1416\cdot 0.8)=\frac{1}{5}=0.2\text{m} \\ {V}_1=S\cdot h=0.5027\cdot 0.2\doteq 0.1005{\text{m}}^3 \\ V=V_1\to \text{l}=V_1\cdot 1000\text{l}=0.1005\cdot 1000\text{l}=100.531\text{l}=100.531\text{l} \end{gathered}$$

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