Two resistors

Two resistors when they give 25 ohms in series and 4 ohms in parallel what the values of

Correct result:

R1 =  20 Ω
R2 =  5 Ω

Solution:

a+b=25 ab/(a+b)=4 a(25a)/25=4  0.04a2+a4=0 0.04a2a+4=0  p=0.04;q=1;r=4 D=q24pr=1240.044=0.36 D>0  a1,2=q±D2p=1±0.360.08 a1,2=12.5±7.5 a1=20 a2=5   Factored form of the equation:  0.04(a20)(a5)=0  R1=a1=20=20 Ω

Our quadratic equation calculator calculates it.

R2=a2=5=5 Ω



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