Deviation 70434

Frustum has the base radii of the figures r1 and r2: r1> r2, r2 = s, and if the side deviation from the base plane is 60°. Express the surface and volume of the cone frustum using its side s.

Correct answer:

S = 18.0642 s^2
V = 4.3078 s^3

Step-by-step explanation:

r1 > r2 r2 = s α=60° rad=60° 180π =60° 1803.1415926 =1.0472=π/3  r1 = s + s cosα k2=1+cosα=1+cos1.0472=23=121=1.5  r1 = 1.5s  sin α= h:s  h = s sin α k1=sinα=sin1.04720.866  h = k1 s  S= π (r12 + r22) + π(r1 + r2).s  k3=π (1.52+12)+π (1.5+1)=3.1416 (1.52+12)+3.1416 (1.5+1)18.0642 S = k3 s2 S=18.0642 s2
V = 31 . π.h .(r12 + r1.r2 + r22) k4=31 π k1 (1.52+1.5 1+12)=31 3.1416 0.866 (1.52+1.5 1+12)4.3078 V = k4 s3 V=4.3078 s3

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