Distance problem 2

A=(x,2x)
B=(2x,1)
Distance AB=√2, find value of x

Correct result:

x1 =  1
x2 =  0

Solution:

(x−2x)2+(2x−1)2=2  (x−2x)2+(2x−1)2=2  5x2−4x−1=0  a=5;b=−4;c=−1 D=b2−4ac=42−4⋅5⋅(−1)=36 D>0  x1,2=−b±D2a=4±3610 x1,2=4±610 x1,2=0.4±0.6 x1=1 x2=−0.2   Factored form of the equation:  5(x−1)(x+0.2)=0  x1=1

Our quadratic equation calculator calculates it.

x2=0

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