Distance problem 2

A=(x,2x)
B=(2x,1)
Distance AB=√2, find value of x

Correct result:

x1 =  1
x2 =  -0.2

Solution:

(x2x)2+(2x1)2=2  (x2x)2+(2x1)2=2  5x24x1=0  a=5;b=4;c=1 D=b24ac=4245(1)=36 D>0  x1,2=b±D2a=4±3610 x1,2=4±610 x1,2=0.4±0.6 x1=1 x2=0.2   Factored form of the equation:  5(x1)(x+0.2)=0  x1=1

Our quadratic equation calculator calculates it.

x2=(0.2)=15=0.2



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