Distance problem

A=(x, x)
B=(1,4)
Distance AB=√5, find x;

Correct result:

x1 =  3
x2 =  2

Solution:

(x1)2+(x4)2=5  (x1)2+(x4)2=5  2x210x+12=0  a=2;b=10;c=12 D=b24ac=1024212=4 D>0  x1,2=b±D2a=10±44 x1,2=10±24 x1,2=2.5±0.5 x1=3 x2=2   Factored form of the equation:  2(x3)(x2)=0  x1=3

Our quadratic equation calculator calculates it.

x2=2x_{2}=2



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