Three points

Three points A (-3;-5) B (9;-10) and C (2;k) . AB=AC
What is value of k?

Correct result:

k1 =  7
k2 =  0

Solution:

d=AB d=(39)2+(5(10))2=13 d2=(32)2+(5k)2  132=(32)2+(5k)2  k210k+119=0 k2+10k119=0  a=1;b=10;c=119 D=b24ac=10241(119)=576 D>0  k1,2=b±D2a=10±5762 k1,2=10±242 k1,2=5±12 k1=7 k2=17   Factored form of the equation:  (k7)(k+17)=0  k1=7

Our quadratic equation calculator calculates it.

k2=0



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Pythagorean theorem is the base for the right triangle calculator.
See also our trigonometric triangle calculator.

 
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