# Square Number

If to a square of integer number add 17, we get the square of next integer number.

What is the original number?

Correct result:

x =  8

#### Solution:

$x^2+17=(x+1)^2 \ \\ x^2+ 17 = x^ + 2x + 1 \ \\ 17-1 = 2x \ \\ \ \\ x = \dfrac{ 17 - 1}{2} = 8$

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