Greatest angle

Calculate the greatest triangle angle with sides 197, 208, 299.

Correct answer:

α =  95.1 °

Step-by-step explanation:

$$\begin{gathered} \mathrm{\Delta }197,208,299:\mathrm{\Delta }197,208,299 \\ {c}^2=a^2+b^2-2ab\cos \alpha \\ \alpha =arccos{\displaystyle \frac{a^2+b^2-c^2}{2bc}}=95.1^{\circ } \end{gathered}$$

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