Suppose 10

Suppose 4+7i is a solution of 5z2+Az+B=0, where A, B∈R. Find A and B.

Final Answer:

A =  -40
B =  325

Step-by-step explanation:

5z2+A⋅ z+B=0 z1​ = 4+7i 5(4+7i)2+A⋅ (4+7i)+B=0 (−165+280i)+4A+7Ai+B=0  −165+4⋅ A+B=0 280+7⋅ A=0  4A+B=165 7A=−280  Pivot:Row1↔Row2  Row2−74​⋅ Row1→Row2 B=325  A=7−280​=−40  A=−40

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