EE school boarding

Three vectors, A, B, and C, are related as follows: A/C = 2 at 120 deg, A + B = -5 + j15, C = conjugate of B. Find C.

Correct answer:

x =  11.9936
y =  2.8868

Step-by-step explanation:

A/C=2 120  A+B = 5+15j C=conj B  W=2  120°  = 2  (cos 120° + j sin 120°)  = 1+1.7320508j W=(1,1.7320508)  A=C   W A+ conj C = 5+j15  5+j15  conj C = C   W  j2 = 1 (a+bj)(c+dj) = (acbd) + (ad+bc)j  C = x+jy 5+j15  (xjy) = (x+jy)   (1+1.7320508j)  x=11.9936 y=2.886752.8868
y==2.8868



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