Petrol and kerosene

What will be the ratio of petrol and kerosene in the final solution formed by mixing petrol and kerosene that are present in three vessels in the ratio 4:1, 5:2, and 6:1, respectively?

Correct answer:

r =  83:22

Step-by-step explanation:

r1=4:1=4 r2=5:2=2.5 r3=6:1=6  V1=V2=V3  P=4+14+5+25+6+16=3583=235132.3714 K=3P=32.3714=35220.6286  r=P:K=2.3714:0.6286=83:223.7727=83:22



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Showing 1 comment:
Dr Math
Another notable solution:

4:1→5, 5:2→7,6:2→7 (add parts: 4+1=5, 5+2=7, 5+2=7)
LCM of 5,7,7=35
P:K -> write also as improper ratios
4:1,→28:7
5:2,→25:10
6:1 →30:5
Finally we get,
P:K=(28+25+30):(7+10+5) = 83:22





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