Lid

What is the weight of concrete cover (lid) to round shape well with a diameter 1.8 m, if the thickness of the cover is 11 cm? 1 m³ of concrete weighs 2190 kg.

Correct result:

m =  613 kg

Solution:

$$\begin{gathered} m=\rho V=\rho \pi r^{2}h \\ m=\pi \cdot 2190\cdot (1.8\mathrm{/}2{)}^2\cdot 11\mathrm{/}100=613\text{ kg} \end{gathered}$$

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