# Trainings

The table contains tennis training schedule for Saturday's younger students during the winter indoor season. Before the start of the summer season is preparing a new training schedule. Tomas Kucera will be able to practice only in the morning, sisters Kovacova will have to train in any order only one after one. Other students meet all times.

How many different schedules tennis training under these conditions can be created for these eight students?

```
9:00 to 9:55 Jana Abrahámová
10:00 to 10:55 Tomas Kucera
11:00 to 11:55 Beata Gross
12:00 to 12:55 Dana Ihringová
13:00 to 13:55 Ingrid Hájková
14:00 to 14:55 Katarina Kovacova
15:00 to 15:55 Zuzana Kovacova
16:00 to 16:55 Peter Valent
```

Result

x =  4080

#### Solution:

Program in PHP:
```for(\$a=1;\$a<=8;\$a++) {
for(\$b=1;\$b<=8;\$b++) {
for(\$c=1;\$c<=8;\$c++) {
for(\$d=1;\$d<=8;\$d++) {
for(\$e=1;\$e<=8;\$e++) {
for(\$f=1;\$f<=8 ;\$f++) {
for(\$g=1;\$g<=8;\$g++) {
for(\$h=1;\$h<=8;\$h++) {

if(\$a != 1 && \$b != 1 && \$c != 1)
{
continue;
}

if(\$a==2 && \$b!=3 || \$b==2 && \$c!=3
|| \$c==2 && \$d!=3 || \$d==2 && \$e!=3 ||
\$e==2 && \$f!=3 || \$f==2 && \$g!=3 ||
\$g==2 && \$h!=3)
{
continue;
}

\$aa = array(\$a, \$b, \$c, \$d, \$e, \$f, \$g, \$h);
if(count(\$aa) != count(array_unique(\$aa)))
{
continue;
}
\$cnt++;

}}}}}}}}
echo 'count of permutations: '.\$cnt;
``` Leave us a comment of example and its solution (i.e. if it is still somewhat unclear...):

Showing 0 comments: Be the first to comment! #### To solve this verbal math problem are needed these knowledge from mathematics:

See also our permutations calculator. See also our variations calculator. Would you like to compute count of combinations?

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