Variations 4/2
Determine the number of elements such that the number of fourth-class variations without repetition is 5112 times greater than the number of second-class variations without repetition.
Your answer:
Your answer:
Tips for related online calculators
Are you looking for help with calculating roots of a quadratic equation?
See also our variations calculator.
Do you have a linear equation or system of equations and are looking for a solution? Or do you have a quadratic equation?
Would you like to compute the count of combinations?
See also our variations calculator.
Do you have a linear equation or system of equations and are looking for a solution? Or do you have a quadratic equation?
Would you like to compute the count of combinations?
You need to know the following knowledge to solve this word math problem:
Related math problems and questions:
- Variations
Find the number of items when the count of variations of the fourth class without repeating is 26 times larger than the count of variations of the third class without repetition. - 2nd class variations
From how many elements can you create 5112 variations of the second class? - Variations Class Comparison
From how many elements can we create six times as many variations of the second class without repetition as variations of the third class without repetition? - Variation element increase
If we increase the number of elements by 2, the number of variations of the second class without repetition increases by 22. How many elements do we have initially? - Combinations
How many elements can form six times more combinations of the fourth class than the combination of the second class? - Set variation increase
If we add one element to set A, the number of third-class variations increases two times. How many elements did the set initially contain? - Variation elements
How many elements do we have if the variation of the third class without repetitions is ten times more than the variation of the second class?
