Variations 4/2

Determine the number of items when the count of variations of fourth class without repeating is 600 times larger than the count of variations of second class without repetition.

Result

n =  27

Solution:

Solution in text n =







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To solve this example are needed these knowledge from mathematics:

Looking for help with calculating roots of a quadratic equation? Would you like to compute count of combinations? See also our variations calculator.

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