Variations 3rd class

From how many elements we can create 13,800 variations 3rd class without repeating?

Correct result:

n =  25

Solution:

V3(n)=n!(n3)!=n(n1)(n2)(n3)!(n3)!=n(n1)(n2)=13800 n(n1)(n2)=13800 n138003=23.986 22n26 V(3,22)=22.21.20=9240 V(3,23)=23.22.21=10626 V(3,24)=24.23.22=12144 V(3,25)=25.24.23=13800 V(3,26)=26.25.24=15600  n=25



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