Variations 3rd class

From how many elements we can create 13,800 variations 3rd class without repeating?

Correct answer:

n =  25

Step-by-step explanation:

V3(n)=n!(n3)!=n(n1)(n2)(n3)!(n3)!=n(n1)(n2)=13800 n(n1)(n2)=13800 n138003=23.986 22n26 V(3,22)=222120=9240 V(3,23)=232221=10626 V(3,24)=242322=12144 V(3,25)=252423=13800 V(3,26)=262524=15600  n=25



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