2nd class combinations

From how many elements can 2346 second-class combinations be formed?

Final Answer:

n =  69

Step-by-step explanation:

(2n​) = 2346   2!⋅ (n−2)!n!​ = 2346   2!⋅ (n−2)!n(n−1)(n−2)!​ = 2346   2n(n−1)​ = 2346  n⋅ (n−1)=2⋅ 2346  n⋅ (n−1)=2⋅ 2346 n2−n−4692=0  a=1;b=−1;c=−4692 D=b2−4ac=12−4⋅1⋅(−4692)=18769 D>0  n1,2​=2a−b±D​​=21±18769​​ n1,2​=21±137​ n1,2​=0.5±68.5 n1​=69 n2​=−68  n>0  n=n1​=69

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