2nd class variations

From how many elements you can create 2450 variations of the second class?

Correct result:

n =  50

Solution:

V2(n)=2450 n(n1)=2450  n (n1)=2450 n2n2450=0  a=1;b=1;c=2450 D=b24ac=1241(2450)=9801 D>0  n1,2=b±D2a=1±98012 n1,2=1±992 n1,2=0.5±49.5 n1=50 n2=49   Factored form of the equation:  (n50)(n+49)=0  n>0 n=n1=50

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