Variations 8333

How many elements do we create 90 variations of 2 classes without repeating elements?

Correct answer:

n =  10

Step-by-step explanation:

V = n (n1) = 90  n (n1)=90  n (n1)=90 n2n90=0  a=1;b=1;c=90 D=b24ac=1241(90)=361 D>0  n1,2=2ab±D=21±361 n1,2=21±19 n1,2=0.5±9.5 n1=10 n2=9  n=n1=10

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