Freight and passenger car

The truck starts at 8 pm at 30 km/h. Passenger car starts at 8 pm at 40 km/h. Passenger arrives in the destination city 1 hour and 45 min earlier. What is the distance between the city of departure and destination city?

Result

s =  210 km

Solution:


30 t = 40 (t-1.75)
s = 30 t

-10t = -70
s-30t = 0

s = 210
t = 7

Calculated by our linear equations calculator.







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