Cable

The cable consists of 5 strands, each strand consisting of 11 wires with a diameter of d = 0.3 mm. Calculate the cross-section of the cable.

Final Answer:

S =  3.9 mm²

Step-by-step explanation:

$$\begin{gathered} d=0.3\text{mm} \\ r=d/2=0.3/2=\frac{3}{20}=0.15\text{mm} \\ {S}_1=\pi \cdot r^2=3.1416\cdot 0.15^2\doteq 0.0707{\text{mm}}^2 \\ S=5\cdot 11\cdot S_1=5\cdot 11\cdot 0.0707=3.9{\text{mm}}^2 \end{gathered}$$

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