Frustum of a cone

A reservoir contains 28.54 m3 of water when completely full. The diameter of the upper base is 3.5 m while at the lower base is 2.5 m. Determine the height if the reservoir is in the form of a frustum of a right circular cone.

Correct result:

h =  4.0005 m

Solution:

V=28.54 m3 D1=3.5 m D2=2.5 m  r1=D1/2=3.5/2=74=1.75 m r2=D2/2=2.5/2=54=1.25 m  V=13 π h(r12+r1 r2+r22)  h=3 Vπ (r12+r1 r2+r22)=3 28.543.1416 (1.752+1.75 1.25+1.252)=4.0005 m



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