Frustum of a cone

A reservoir contains 28.54 m3 of water when full. The diameter of the upper base is 3.5 m, while at the lower base is 2.5 m. Find the height if the reservoir is in the form of a frustum of a right circular cone.

Correct result:

h =  4.0005 m

Solution:

V=28.54 m3 D1=3.5 m D2=2.5 m  r1=D1/2=3.5/2=74=1.75 m r2=D2/2=2.5/2=54=1.25 m  V=13 π h(r12+r1 r2+r22)  h=3 Vπ (r12+r1 r2+r22)=3 28.543.1416 (1.752+1.75 1.25+1.252)=4.0005 m



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