Frustum of a cone

A reservoir contains 28.54 m3 of water when complete. The diameter of the upper base is 3.5 m, while the lower base is 2.5 m. Find the height if the reservoir is in the form of a frustum of a right circular cone.

Correct answer:

h =  4.0005 m

Step-by-step explanation:

V=28.54 m3 D1=3.5 m D2=2.5 m  r1=D1/2=3.5/2=47=1.75 m r2=D2/2=2.5/2=45=1.25 m  V = 31   π   h ( r12 + r1 r2 + r22)  h=π (r12+r1 r2+r22)3 V=3.1416 (1.752+1.75 1.25+1.252)3 28.54=4.0005 m

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Q: Why are they (r2+r)?

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