1st drug

First drug pack has an active ingredient ratio of L1: L2 = 2: 1
Second drug pack have a ratio of active ingredients L1: L2 = 1: 3

In which ratio do we have to mix the two packages so that the ratio of substances L1: L2 = 1: 2?

Correct result:

r =  1:4

Solution:

 L1=x (2/(2+1))+y (1/(1+3)) L2=x (1/(2+1)+y 3/(1+3)  23x+14y=12 (13x+34y)  r=x/y 23r+14=12 (13r+34)   2/3 r+1/4=1/2 (r/3+3/4)  6r=1.5  r=14=0.25=1:4



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