1st drug

The first drug pack has an active ingredient ratio of L1: L2 = 2:1
The second drug pack has a ratio of active ingredients L1: L2 = 1:3

Which ratio do we have to mix the two packages so that the ratio of substances L1: L2 = 1:2?

Correct answer:

r =  1:4

Step-by-step explanation:

L1 = x   (2/(2+1)) + y (1/(1+3)) L2 = x (1/(2+1) + y 3/(1+3)  32x + 41y = 21   (31x + 43y)  r = x/y 32r + 41 = 21   (31r + 43)  2/3 r+1/4=1/2 (r/3+3/4)  6r=1.5  r=61.5=0.25  r=41=0.25=1:4

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