Axial section

Axial section of the cylinder has a diagonal 40 cm. The size of the shell and the base surface are in the ratio 3:2.

Calculate the volume and surface area of this cylinder.

Correct result:

S =  3855.98 cm2
V =  15473.44 cm3

Solution:

402=h2+(2r)2 S1S2=32 2πrhπr2=32 2hr=32 r=2h23  r2=h2+16h222/32=h2(1+1622/32) h=401+1622/32=14.045 cm r=2h23=18.727 cm  S=2πr2+2πrh=3855.98 cm2 
V=πr2h=15473.44 cm3



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