Chord 3

What is the radius of the circle where the chord is 2/3 of the radius from the center and has a length of 10 cm?

Result

r =  6.71 cm

Solution:

r2=(10/2)2+(2/3r)2 r2(1−4/9)=52 r=51−4/9 r=6.71 cmr^2 = (10/2)^2+(2/3r)^2 \ \\ r^2 ( 1- 4/9) = 5^2 \ \\ r = \dfrac{5}{ \sqrt{ 1- 4/9}} \ \\ r = 6.71 \ \text{cm}

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