The rescue helicopter

The rescue helicopter is above the landing site at a height of 180m. The site of the rescue operation can be seen from here at a depth angle of 52° 40 '. How far will the helicopter land from the rescue site?

Correct result:

x =  137 m

Solution:

$$\begin{gathered} y=180\text{ m } \\ A=52+40\mathrm{/}60={\displaystyle \frac{158}{3}}\doteq 52.6667^{\circ } \\ \tan A=y:x \\ x=y\mathrm{/}\tan A^{\circ }=y\mathrm{/}\tan 52.6666666667^{\circ }=180\mathrm{/}\tan 52.6666666667^{\circ }=180\mathrm{/}1.311105=137=137\text{ m} \end{gathered}$$

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