The rescue helicopter

The rescue helicopter is above the landing site at a height of 180m. The site of the rescue operation can be seen from here at a depth angle of 52° 40 '. How far will the helicopter land from the rescue site?

Result

x =  137 m

Solution:

y=180 m A=52+40/60=1583≐52.6667 ∘  tan⁡A=y:x  x=y/tan⁡A∘=y/tan⁡52.6666666667∘ =180/tan⁡52.6666666667∘ =y/1.311105=137.28882=137 my=180 \ \text{m} \ \\ A=52+40/60=\dfrac{ 158 }{ 3 } \doteq 52.6667 \ ^\circ \ \\ \ \\ \tan A=y:x \ \\ \ \\ x=y/ \tan A ^\circ =y/ \tan 52.6666666667^\circ \ =180/ \tan 52.6666666667^\circ \ =y/ 1.311105=137.28882=137 \ \text{m}

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