Oak trunk

Calculate in tonnes the approximate weight of a cylindrical oak trunk with a diameter of 66 cm and a length of 4 m, knowing that the density of the wood was 800 kg/m³.

Result

m =  1.095 t

Solution:

D=66 cmm=66/100 m=0.66 m l=4 m ρ=800 kg/m3  r=D/2=0.66/2=33100=0.33 m S=π r2=3.1416 0.3320.3421 m2  V=S l=0.3421 41.3685 m3 m1=V ρ=1.3685 8001094.7822 kg  m=m1t=m1/1000 t=1094.78220792/1000 t=1.09478 t=1.095 tD=66 \ cm \rightarrow m=66 / 100 \ m=0.66 \ m \ \\ l=4 \ \text{m} \ \\ ρ=800 \ \text{kg/m}^3 \ \\ \ \\ r=D/2=0.66/2=\dfrac{ 33 }{ 100 }=0.33 \ \text{m} \ \\ S=\pi \cdot \ r^2=3.1416 \cdot \ 0.33^2 \doteq 0.3421 \ \text{m}^2 \ \\ \ \\ V=S \cdot \ l=0.3421 \cdot \ 4 \doteq 1.3685 \ \text{m}^3 \ \\ m_{1}=V \cdot \ ρ=1.3685 \cdot \ 800 \doteq 1094.7822 \ \text{kg} \ \\ \ \\ m=m_{1} \rightarrow t=m_{1} / 1000 \ t=1094.78220792 / 1000 \ t=1.09478 \ t=1.095 \ \text{t}



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