Truncated pyramid

How many cubic meters is the volume of a regular four-sided truncated pyramid with edges one meter and 60 cm and high 250 mm?

Correct result:

V =  0.1633 m³

Solution:

$$\begin{gathered} a_1=1\text{ m } \\ {a}_2=60\mathrm{/}100={\displaystyle \frac{3}{5}}=0.6\text{ m } \\ h=250\mathrm{/}1000={\displaystyle \frac{1}{4}}=0.25\text{ m } \\ {S}_1=a_1^2=1^2=1{\text{m}}^2 \\ {S}_2=a_2^2=0.6^2={\displaystyle \frac{9}{25}}=0.36{\text{m}}^2 \\ V=h\mathrm{/}3\cdot (S_1+\sqrt{S_1\cdot S_2}+S_2)=0.25\mathrm{/}3\cdot (1+\sqrt{1\cdot 0.36}+0.36)={\displaystyle \frac{49}{300}}=0.1633{\text{m}}^3 \end{gathered}$$

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