Truncated pyramid

How many cubic meters is the volume of a regular four-sided truncated pyramid with edges one meter and 60 cm and high 250 mm?

Correct result:

V =  0.1633 m3

Solution:

a1=1 m a2=60/100=35=0.6 m h=250/1000=14=0.25 m  S1=a12=12=1 m2 S2=a22=0.62=925=0.36 m2  V=h/3⋅ (S1+S1⋅ S2+S2)=0.25/3⋅ (1+1⋅ 0.36+0.36)=49300=0.1633 m3

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