Rectangle SS

The perimeter of a rectangle is 154 dm and its diagonal is 62.36 dm. Find the dimensions of the rectangle.

Final Answer:

a =  59.9973 dm
b =  17.0027 dm

Step-by-step explanation:

o=154 dm u=62.36 dm  2(a+b)=o a2+b2 = u2  b= o/2−a a2+b2 = u2  a2+(o/2−a)2=u2  a2+(154/2−a)2=62.362 2a2−154a+2040.23=0  p=2;q=−154;r=2040.23 D=q2−4pr=1542−4⋅2⋅2040.23=7394.1568 D>0  a1,2​=2p−q±D​​=4154±7394.16​​ a1,2​=38.5±21.497321 a1​=59.997320763 a2​=17.002679237  a=a1​=59.9973=59.9973 dm

Our quadratic equation calculator calculates it.

b=o/2−a=154/2−59.9973≐17.0027 dm   Verifying Solution:  o2​=2⋅ (a+b)=2⋅ (59.9973+17.0027)=154 dm u2​=a2+b2​=59.99732+17.00272​=251559​=62.36 dm

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algebraarithmeticplanimetricsnumbersUnits of physical quantitiesGrade of the word problem

 
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