Edge of prism

The regular quadrilateral prism has a surface of 250 dm², its shell has a content of 200 dm². Calculate its leading edge.

Correct answer:

a =  5 dm

Step-by-step explanation:

$$\begin{gathered} S_1=250{\text{dm}}^2 \\ {S}_2=200{\text{dm}}^2 \\ {S}_1=2\cdot a^2+S_2 \\ a=\sqrt{(S_1-S_2)\mathrm{/}2}=\sqrt{(250-200)\mathrm{/}2}=5\text{ dm} \end{gathered}$$

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