Edge of prism

The regular quadrilateral prism has a surface of 250 dm2. Its shell has an area of 200 dm2. Calculate its leading edge.

Correct answer:

a =  5 dm

Step-by-step explanation:

S1=250 dm2 S2=200 dm2  S1=2 a2+S2  a=(S1S2)/2=(250200)/2=5 dm



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