Edge of prism

The regular quadrilateral prism has a surface of 250 dm2, its shell has a content of 200 dm2. Calculate its leading edge.

Correct result:

a =  5 dm

Solution:

S1=250 dm2 S2=200 dm2  S1=2⋅ a2+S2  a=(S1−S2)/2=(250−200)/2=5 dm

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