Find the

Find the surface area of a regular quadrilateral pyramid which has a volume of 24 dm3 and a height of 45 cm.

Correct result:

S =  5539.5431 cm2

Solution:

V=24 dm3 cm3=24 1000  cm3=24000 cm3 h=45 cm  V=13 S1 h  S1=3 V/h=3 24000/45=1600 cm2  S1=a2  a=S1=1600=40 cm  (a/2)2+h2=h22  h2=(a/2)2+h2=(40/2)2+452=5 97 cm49.2443 cm  S2=a h22=40 49.24432=100 97 cm2984.8858 cm2  S=4 S2+S1=4 984.8858+1600=5539.5431 cm2



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