Regular quadrilateral pyramid

Find the surface area of a regular quadrilateral pyramid with a volume of 24 dm3 and a height of 45 cm.

Correct answer:

S =  5539.5431 cm2

Step-by-step explanation:

V=24 dm3 cm3=24 1000  cm3=24000 cm3 h=45 cm  V = 31   S1   h  S1=3 V/h=3 24000/45=1600 cm2  S1 = a2  a=S1=1600=40 cm  (a/2)2 + h2 = h22  h2=(a/2)2+h2=(40/2)2+452=5 97 cm49.2443 cm  S2=2a h2=240 49.2443=100 97 cm2984.8858 cm2  S=4 S2+S1=4 984.8858+1600=5539.5431 cm2

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