Horizontal Cylindrical Segment

How much fuel is in the tank of horizontal cylindrical segment with a length 10m, width of level 1 meter and level is 0.2 meters below the upper side of the tank?

Correct result:

V =  15.1379 m3

Solution:

a=10 s=1 h=0.2 r2=(s/2)2+(r−h)2 r2=0.25+(r−0.2)2 r=0.725 H=2⋅ r−h=2⋅ 0.725−0.2=54=1.25 A=r2⋅ arccos⁡((r−h)/r)=0.7252⋅ arccos⁡((0.725−0.2)/0.725)≐0.4 B=(r−h)⋅ 2⋅ r⋅ h−h2=(0.725−0.2)⋅ 2⋅ 0.725⋅ 0.2−0.22=2180=0.2625 S1=A−B=0.4−0.2625≐0.1375 S2=π⋅ r2=3.1416⋅ 0.7252≐1.6513 S=S2−S1=1.6513−0.1375≐1.5138 V=S⋅ a=1.5138⋅ 10=15.1379 m3

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