Regular quadrilateral pyramid

Find the volume and surface of a regular quadrilateral pyramid if the bottom edge is 45 cm long and the pyramid height is 7 cm.

Correct result:

V =  4725 cm3
S =  4145.7369 cm2

Solution:

a=45 cm h=7 cm S1=a2=452=2025 cm2 V=S1 h/3=2025 7/3=4725 cm3
h2=h2+(a/2)2=72+(45/2)223.5637 cm S2=a h2/2=45 23.5637/2530.1842 cm2 S=S1+4 S2=2025+4 530.1842=4145.7369 cm2



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