Common chord

Two circles with radii 18 cm and 20 cm intersect at two points. Its common chord is long 11 cm. What is the distance of the centers of these circles?

Correct answer:

x =  36.4 cm

Step-by-step explanation:

r1=18 cm r2=20 cm t=11 cm  x12 = r12  (t/2)2 x22 = r22  (t/2)2  x1=r12(t/2)2=182(11/2)217.1391 cm x2=r22(t/2)2=202(11/2)219.2289 cm  x=x1+x2=17.1391+19.2289=36.4 cm

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