Truncated cone

Find the volume and surface area of the truncated cone if r1 = 12 cm, r2 = 5 cm and side s = 10 cm.

Correct result:

V =  1712.5734 cm3
S =  1064.9999 cm2

Solution:

r1=12 cm r2=5 cm s=10 cm  s2=h2+(r1r2)2 h=s2(r1r2)2=102(125)2=51 cm7.1414 cm  V=π h3 (r12+r1 r2+r22)=3.1416 7.14143 (122+12 5+52)=1712.5734 cm3
S=π r12+π r22+π (r1+r2) h2+(r1r2)2=3.1416 122+3.1416 52+3.1416 (12+5) 7.14142+(125)2=1064.9999 cm2



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