Rectangle diagonals

It is given rectangle with area 24 cm2 a circumference 20 cm. The length of one side is 2 cm larger than length of second side. Calculate the length of the diagonal. Length and width are yet expressed in natural numbers.

Correct result:

u =  7.2111 cm

Solution:

S=24 o=20 S=ab o=2(a+b) b=10a 24=a(10a)  24=a (10a) a210a+24=0  p=1;q=10;r=24 D=q24pr=1024124=4 D>0  a1,2=q±D2p=10±42 a1,2=10±22 a1,2=5±1 a1=6 a2=4   Factored form of the equation:  (a6)(a4)=0 a=a1=6 b=10a=106=4 u=a2+b2=62+42=2 13=7.2111 cm

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