2d shape

Calculate the content of a shape in which an arbitrary point is not more than 3 cm from the segment AB. The length of the segment AB is 5 cm.

Result

S =  58.274 cm2

Solution:

a=5 r=3 S1=a 2 r=5 2 3=30 S2=π r2=3.1416 3228.2743 S=S1+S2=30+28.274358.274358.274 cm2a=5 \ \\ r=3 \ \\ S_{1}=a \cdot \ 2 \cdot \ r=5 \cdot \ 2 \cdot \ 3=30 \ \\ S_{2}=\pi \cdot \ r^2=3.1416 \cdot \ 3^2 \doteq 28.2743 \ \\ S=S_{1}+S_{2}=30+28.2743 \doteq 58.2743 \doteq 58.274 \ \text{cm}^2



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