# Forces on earth directions

A force of 60 N [North] and 80 N [East] is exerted on an object wigth 10 kg. What is the acceleration of the object?

Result

a =  10 m/s2

#### Solution:

$m=10 \ \text{kg} \ \\ F_{1}=60 \ \text{N} \ \\ F_{2}=80 \ \text{N} \ \\ \ \\ F=\sqrt{ F_{1}^2+F_{2}^2 }=\sqrt{ 60^2+80^2 }=100 \ \text{N} \ \\ F=m a \ \\ a=F/m=100/10=10 \ \text{m/s}^2$

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Tips to related online calculators
Two vectors given by its magnitudes and by included angle can be added by our vector sum calculator.
Pythagorean theorem is the base for the right triangle calculator.

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