Hypotenuse and height

In a right triangle is length of the hypotenuse c = 56 cm and height h_c = 4 cm. Determine the length of both trangle legs.

Correct result:

a =  55.9 cm
b =  4 cm

Solution:

$56=x+y \ \\ 4^2=xy \ \\ \ \\ x(56-x) = 4^2 \ \\ \ \\ x^2 -56x +16 =0 \ \\ \ \\ a=1; b=-56; c=16 \ \\ D = b^2 - 4ac = 56^2 - 4\cdot 1 \cdot 16 = 3072 \ \\ D>0 \ \\ \ \\ x_{1,2} = \dfrac{ -b \pm \sqrt{ D } }{ 2a } = \dfrac{ 56 \pm \sqrt{ 3072 } }{ 2 } = \dfrac{ 56 \pm 32 \sqrt{ 3 } }{ 2 } \ \\ x_{1,2} = 28 \pm 27.7128129211 \ \\ x_{1} = 55.7128129211 \ \\ x_{2} = 0.287187078898 \ \\ \ \\ \text{ Factored form of the equation: } \ \\ (x -55.7128129211) (x -0.287187078898) = 0 \ \\ \ \\ \ \\ a = \sqrt{ x_1 \cdot 56 } = 55.9 \ \text{cm}$

$b=\sqrt{x_2\cdot 56}=4\text{ cm}$

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