Largest angle of the triangle

Calculate the largest angle of the triangle whose sides have the sizes:
2a, 3/2a, 3a

Correct result:

C =  117.2796 °

Solution:

x=1 a=2⋅ x=2⋅ 1=2 b=3/2⋅ x=3/2⋅ 1=32=1.5 c=3⋅ x=3⋅ 1=3  c>a>b c2=a2+b2−2⋅ a⋅ b⋅ cos⁡(C) C=180∘π⋅arccos⁡(a2+b2−c22⋅ a⋅ b)=180∘π⋅arccos⁡(22+1.52−322⋅ 2⋅ 1.5)=117.2796∘=117∘16′47"

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