Largest angle of the triangle

Calculate the largest angle of the triangle whose sides have the sizes:
2a, 3/2a, 3a

Correct result:

C =  117.2796 °

Solution:

x=1 a=2 x=2 1=2 b=3/2 x=3/2 1=32=1.5 c=3 x=3 1=3  c>a>b c2=a2+b22 a b cos(C) C=180πarccos(a2+b2c22 a b)=180πarccos(22+1.52322 2 1.5)=117.2796=1171647"

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