Largest angle of the triangle

Calculate the largest angle of the triangle whose sides have the sizes:
2a, 3/2a, 3a

Correct answer:

C =  117.2796 °

Step-by-step explanation:

x=1 a=2 x=2 1=2 b=3/2 x=3/2 1=23=1.5 c=3 x=3 1=3 =0 c>a>b c2 = a2+b2  2 a b cos(C) C=π180°arccos(2 a ba2+b2c2)=π180°arccos(2 2 1.522+1.5232)=117.2796=117°1647"

= 0

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