Quadrilateral 6332

The regular quadrilateral pyramid is 2 m high. The height of the sidewall is 2.8 m. What are the dimensions of the base? Calculate the surface area and volume of the pyramid.

Correct answer:

a =  3.9192 m
S =  37.3074 m2
V =  10.24 m3

Step-by-step explanation:

h1=2 m h2=2.8 m  (a/2)2 + h12  = h22  a=2 h22h12=2 2.8222=3.9192 m
S1=a2=3.91922=25384=15.36 m2 S2=a h2/2=3.9192 2.8/25.4869 m2  S=S1+4 S2=15.36+4 5.4869=37.3074 m2
V=31 S1 h1=31 15.36 2=25256 m3=10.24 m3

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