Find radius of circle using pythagorean theorem where a=9, b=r, c= 6+r

Correct result:

r =  3.75

#### Solution:

$a^b+b^2=c^2 \ \\ a=9 \ \\ \ \\ 9^2 + r^2=(6+r)^2 \ \\ 12r=45 \ \\ r=45/12=\dfrac{ 15 }{ 4 }=3.75$

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