Find the 13

Find the equation of the circle inscribed in the rhombus ABCD where A[1, -2], B[8, -3] and C[9, 4].

Result

e = (Correct answer is: ) OK

Step-by-step explanation:

A=(1,2) B=(8,3) C=(9,4) S=(A+C)/2 x0=(Ax+Cx)/2=(1+9)/2=5 y0=(Ay+Cy)/2=((2)+4)/2=1  AB: a=1  a Ax+b Ay+c=0 a Bx+b By+c=0 1 1+b (2)+c=0 1 8+b (3)+c=0  2bc=1 3bc=8  b=7 c=13  AB:x+7y+13=0  v=a2+b2=12+72=5 27.0711  r=va x0+b y0+c=7.07111 5+7 1+133.5355  R=r2=3.53552=225=1221=12.5  e:(xx0)2+(yy0)2=r2 e:(x5)2+(y1)2=12.5=25:2



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Showing 1 comment:
Ema
I think the coordinate of D is (2,5) and ABCD is a square with side length of 5.sqrt(2) and the circle's radius is 5/sqrt(2). The equation of circle will be (x-5)2 + (y-1)2 = 25/2





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