Diagonals at right angle

In the trapezoid ABCD this is given:
AB=12cm
CD=4cm
And diagonals crossed under a right angle. What is the area of this trapezoid ABCD?

Correct result:

S =  64 cm2

Solution:

a=12 cm c=4 cm  a:c=h1:h2  h=h1+h2  h1=a/2=12/2=6 cm h2=c/2=4/2=2 cm  h=h1+h2=6+2=8 cm  S=a+c2⋅ h=12+42⋅ 8=64 cm2

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